# Thread: Check my answer on finding the area of an isoscels triangle?

1. ## Check my answer on finding the area of an isoscels triangle?

Has a base of 6 cm, and has a semi-perimeter of 11cm. What is the area?

Sq. Rt. 11(11-6)(11-6)(11-6)
Sq. Rt. 11(5)(5)(5)
sq. rt. 11 * sq. rt. 125 = 37.1 cm^2

2. ## Re: Check my answer on finding the area of an isoscels triangle?

the triangle is not equilateral ...

2x + 6 = 22

x = 8

the sides are 8, 8, and 6

3. ## Re: Check my answer on finding the area of an isoscels triangle?

So the answer would be 22.2cm^2 ?

4. ## Re: Check my answer on finding the area of an isoscels triangle?

Yes.

$\text{area} = \sqrt{s\left(s-a\right)\left(s-b\right)\left(s-c\right)}$
$= \sqrt{11(3)(3)(5)}$
$= 3 * \sqrt{55}$