Has a base of 6 cm, and has a semi-perimeter of 11cm. What is the area?
Sq. Rt. 11(11-6)(11-6)(11-6)
Sq. Rt. 11(5)(5)(5)
sq. rt. 11 * sq. rt. 125 = 37.1 cm^2
Yes.
$\displaystyle \text{area} = \sqrt{s\left(s-a\right)\left(s-b\right)\left(s-c\right)}$
$\displaystyle = \sqrt{11(3)(3)(5)}$
$\displaystyle = 3 * \sqrt{55}$
which is equal to your answer.