How would you find the period of the trig function 2cos1/3x? And sinπx/24?
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For $\displaystyle y=A\sin(Bx)$ or $\displaystyle y=A\cos(Bx)$, the period $\displaystyle T$ is: $\displaystyle T=\frac{2\pi}{B}$
Ok, so the period for the first equation is 2pi/(1/3)? And the second is 2pi/(xpi/24)?
For the first, you may simplify by using 1/(1/3) = 3, and for the second, you do not include x, and you may divide out pi, and bring the 24 up to the numerator.
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