How would you find the period of the trig function 2cos1/3x? And sinπx/24?
Follow Math Help Forum on Facebook and Google+
For or , the period is:
Ok, so the period for the first equation is 2pi/(1/3)? And the second is 2pi/(xpi/24)?
For the first, you may simplify by using 1/(1/3) = 3, and for the second, you do not include x, and you may divide out pi, and bring the 24 up to the numerator.
View Tag Cloud