@skeeter: Yes , but then I'm left w/ (cosxcotx(secx-tanx) + sinx(sexc + tanx). I tried putting all of tht in terms of sin & cos & eventually reached the point [(cos^2x(cosx-sinx)+ sin^2x(1+sinx)]/(sinxcosx)]
Yes, when you double post, and your duplicate post gets deleted, then the help in the duplicate gets deleted as well, wasting time and effort of those trying to help.