I need help simplifying this trig expression. I started by trying to find a common denom. btwn the two fractions
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Originally Posted by hunnyelle Simplify [(cosxcotx)/(secx+tanx)] + (sinx)/(secx-tanx)]
I need help simplifying this trig expression. I started by trying to find a common denom. btwn the two fractions note that your common denominator, equals 1
btw ... do not double post.
Last edited by skeeter; Nov 13th 2012 at 03:30 PM.
@skeeter: Yes , but then I'm left w/ (cosxcotx(secx-tanx) + sinx(sexc + tanx). I tried putting all of tht in terms of sin & cos & eventually reached the point [(cos^2x(cosx-sinx)+ sin^2x(1+sinx)]/(sinxcosx)]
Yes, when you double post, and your duplicate post gets deleted, then the help in the duplicate gets deleted as well, wasting time and effort of those trying to help.
I don't think changing every term to sines and cosines will do much good from this point ... do you know what it is supposed to simplify to?
The answer is cotx -cosx + tanx +sinxtanx, & I've figured out how to reach that answer!
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