1. Simplify [(cosxcotx)/(secx+tanx)] + (sinx)/(sex-tanx)]

I need help simplifying this trig expression. I started by trying to find a common denom. btwn the two fractions

2. Re: Simplify [(cosxcotx)/(secx+tanx)] + (sinx)/(sex-tanx)]

Originally Posted by hunnyelle
Simplify [(cosxcotx)/(secx+tanx)] + (sinx)/(secx-tanx)]

I need help simplifying this trig expression. I started by trying to find a common denom. btwn the two fractions
note that your common denominator, $\displaystyle \sec^2{x} - \tan^2{x}$ equals 1

btw ... do not double post.

3. Re: Simplify [(cosxcotx)/(secx+tanx)] + (sinx)/(sex-tanx)]

@skeeter: Yes , but then I'm left w/ (cosxcotx(secx-tanx) + sinx(sexc + tanx). I tried putting all of tht in terms of sin & cos & eventually reached the point [(cos^2x(cosx-sinx)+ sin^2x(1+sinx)]/(sinxcosx)]

4. Re: Simplify [(cosxcotx)/(secx+tanx)] + (sinx)/(sex-tanx)]

Yes, when you double post, and your duplicate post gets deleted, then the help in the duplicate gets deleted as well, wasting time and effort of those trying to help.

5. Re: Simplify [(cosxcotx)/(secx+tanx)] + (sinx)/(sex-tanx)]

$\displaystyle \cos{x}\cot{x}(\sec{x}-\tan{x}) + \sin{x}(\sec{x}+\tan{x})$

$\displaystyle \cos{x}\cot{x}\sec{x} - \cos{x}\cot{x}\tan{x} + \sin{x}\sec{x} + \sin{x}\tan{x}$

$\displaystyle \cot{x} - \cos{x} + \tan{x} + \sin{x}\tan{x}$

$\displaystyle \cot{x}(1 - \sin{x}) + \tan{x}(1 + \sin{x})$

I don't think changing every term to sines and cosines will do much good from this point ... do you know what it is supposed to simplify to?

6. Re: Simplify [(cosxcotx)/(secx+tanx)] + (sinx)/(sex-tanx)]

The answer is cotx -cosx + tanx +sinxtanx, & I've figured out how to reach that answer!

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www.sixnx fuck foram.com

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