I need help simplifying this trig expression. I started by trying to find a common denom. btwn the two fractions

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- Nov 13th 2012, 03:19 PMhunnyelleSimplify [(cosxcotx)/(secx+tanx)] + (sinx)/(sex-tanx)]
I need help simplifying this trig expression. I started by trying to find a common denom. btwn the two fractions

- Nov 13th 2012, 03:24 PMskeeterRe: Simplify [(cosxcotx)/(secx+tanx)] + (sinx)/(sex-tanx)]
- Nov 13th 2012, 03:31 PMhunnyelleRe: Simplify [(cosxcotx)/(secx+tanx)] + (sinx)/(sex-tanx)]
@skeeter: Yes , but then I'm left w/ (cosxcotx(secx-tanx) + sinx(sexc + tanx). I tried putting all of tht in terms of sin & cos & eventually reached the point [(cos^2x(cosx-sinx)+ sin^2x(1+sinx)]/(sinxcosx)]

- Nov 13th 2012, 03:52 PMMarkFLRe: Simplify [(cosxcotx)/(secx+tanx)] + (sinx)/(sex-tanx)]
Yes, when you double post, and your duplicate post gets deleted, then the help in the duplicate gets deleted as well, wasting time and effort of those trying to help.

- Nov 13th 2012, 03:52 PMskeeterRe: Simplify [(cosxcotx)/(secx+tanx)] + (sinx)/(sex-tanx)]
$\displaystyle \cos{x}\cot{x}(\sec{x}-\tan{x}) + \sin{x}(\sec{x}+\tan{x})$

$\displaystyle \cos{x}\cot{x}\sec{x} - \cos{x}\cot{x}\tan{x} + \sin{x}\sec{x} + \sin{x}\tan{x}$

$\displaystyle \cot{x} - \cos{x} + \tan{x} + \sin{x}\tan{x}$

$\displaystyle \cot{x}(1 - \sin{x}) + \tan{x}(1 + \sin{x})$

I don't think changing every term to sines and cosines will do much good from this point ... do you know what it is supposed to simplify to? - Nov 13th 2012, 04:06 PMhunnyelleRe: Simplify [(cosxcotx)/(secx+tanx)] + (sinx)/(sex-tanx)]
The answer is cotx -cosx + tanx +sinxtanx, & I've figured out how to reach that answer!