1. verifying trig identities

How would you verify sec-1/tan=tan/sec+1? also how would you verify 8sin^2cos^2=1-cos4?

2. Re: verifying trig identities

sec is the abbreviation for second

tan is what one may get while visiting the beach

sin is a transgression

cos is the nickname of a famous black comedian

... in other words, a trig function without an argument means nothing.

now, if you meant ...

$\frac{\sec{x} - 1}{\tan{x}} = \frac{\tan{x}}{\sec{x} + 1}$

... then I recommend multiplying the left side of the equation by $\frac{\sec{x}+1}{\sec{x}+1}$, then using the Pythagorean identity
$1+\tan^2{x} = \sec^2{x}$

now, can you be more clear with this equation ...

how would you verify 8sin^2cos^2=1-cos4?

3. Re: verifying trig identities

The question just has 8(sin^2 x)(cos^2 x)= 1-cos 4x.

4. Re: verifying trig identities

Originally Posted by derek1008
The question just has 8(sin^2 x)(cos^2 x)= 1-cos 4x.
much better ...

$1 - \cos(4x) =$

$2\left(\frac{1-\cos(4x)}{2}\right) =$

$2\sin^2(2x) =$

$2(2\sin{x}\cos{x})^2 =$

$8\sin^2{x}\cos^2{x}$

5. Re: verifying trig identities

Originally Posted by skeeter
... in other words, a trig function without an argument means nothing.
so if we fight over cosines, then it's meaningful? :P

6. Re: verifying trig identities

Originally Posted by Deveno
so if we fight over cosines, then it's meaningful? :P
Deveno, you're a much better mathematician than comedian ... don't quit your day job.

7. Re: verifying trig identities

but there's a method to my madness: the definition of a function f doesn't really "depend" on its argument.

for example, we can talk of the "squaring function" f (usually written as f(x) = x2) as [ ]2 (although this is a bit confusing).

for example (and more to the point in this case):

the fundamental trig identity can be written as:

cos2 + sin2 = 1, meaning:

cos2(x) + sin2(x) is the CONSTANT function 1, no matter WHAT "x" is (and the symbol we use in place of x really doesn't matter, it could be t, or θ, or Y, it's a "dummy variable").

the equation:

cos2(x) + sin2(x) = 1 is an equality of two NUMBERS.

the equation:

cos2 + sin2 = 1 is an equality between two FUNCTIONS.

the first means it just happens to be true for some particular x (which turns out to be all of them).

the second means the two functions (and we sum two functions f+g by summing the values f(x) + g(x) at each point x) sum to a constant function.

granted, people are used to confusing a function with its value at a point. and your point is well taken that the original poster was probably just "being lazy" in omitting the argument.

still, it's not entirely wrong.

(how's THAT for an argument? see what i did there?)

8. Re: verifying trig identities

sure do ... but I'd still mark off points for leaving out the x (or t or theta). Plato gets upset if one writes $\cos{x}$ instead of $\cos(x)$ ... we all have our quirks.

9. Re: verifying trig identities

well, there is a reason for these things. for example, in modelling a physical situation, if one writes cos(t), the "t" is there presumably to remind you which UNITS "t" is in (often, in physics for example, one may have equations with respect to several variables at once, but one is considering some of the variables as "variable constants" or parameters chosen before-hand, whereas the independent variable might take on any value in the domain, so you can have cos(ωt), where ω is "fixed" but "t" is a "true variable", which might be important when differentiating).

of course, trigonometry is peculiar, too, it is one place where cos2(x) means: (cos(x))(cos(x)), and not cos(cos(x)), like it would in other areas.

10. Re: verifying trig identities

I don't get why you multiplied it by secx+1/ secx+1?

11. Re: verifying trig identities

Originally Posted by WhatthePatel
I don't get why you multiplied it by secx+1/ secx+1?
because $(\sec{x}-1)(\sec{x}+1) = \sec^2{x} - 1 = \tan^2{x}$