How would you verify sec-1/tan=tan/sec+1? also how would you verify 8sin^2cos^2=1-cos4?

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- November 13th 2012, 01:52 PMderek1008verifying trig identities
How would you verify sec-1/tan=tan/sec+1? also how would you verify 8sin^2cos^2=1-cos4?

- November 13th 2012, 02:10 PMskeeterRe: verifying trig identities
**sec**is the abbreviation for second

**tan**is what one may get while visiting the beach

**sin**is a transgression

**cos**is the nickname of a famous black comedian

... in other words, a trig function without an argument means nothing.

now, if you meant ...

... then I recommend multiplying the left side of the equation by , then using the Pythagorean identity

now, can you be more clear with this equation ...

Quote:

how would you verify 8sin^2cos^2=1-cos4?

- November 13th 2012, 02:42 PMderek1008Re: verifying trig identities
The question just has 8(sin^2 x)(cos^2 x)= 1-cos 4x.

- November 13th 2012, 03:18 PMskeeterRe: verifying trig identities
- November 13th 2012, 03:52 PMDevenoRe: verifying trig identities
- November 13th 2012, 03:57 PMskeeterRe: verifying trig identities
- November 13th 2012, 04:21 PMDevenoRe: verifying trig identities
but there's a method to my madness: the definition of a function f doesn't really "depend" on its argument.

for example, we can talk of the "squaring function" f (usually written as f(x) = x^{2}) as [ ]^{2}(although this is a bit confusing).

for example (and more to the point in this case):

the fundamental trig identity can be written as:

cos^{2}+ sin^{2}= 1, meaning:

cos^{2}(x) + sin^{2}(x) is the CONSTANT function 1, no matter WHAT "x" is (and the symbol we use in place of x really doesn't matter, it could be t, or θ, or Y, it's a "dummy variable").

the equation:

cos^{2}(x) + sin^{2}(x) = 1 is an equality of two NUMBERS.

the equation:

cos^{2}+ sin^{2}= 1 is an equality between two FUNCTIONS.

the first means it just happens to be true for some particular x (which turns out to be all of them).

the second means the two functions (and we sum two functions f+g by summing the values f(x) + g(x) at each point x) sum to a constant function.

granted, people are used to confusing a function with its value at a point. and your point is well taken that the original poster was probably just "being lazy" in omitting the argument.

still, it's not entirely wrong.

(how's THAT for an argument? see what i did there?) - November 13th 2012, 04:29 PMskeeterRe: verifying trig identities
sure do ... but I'd still mark off points for leaving out the x (or t or theta). Plato gets upset if one writes instead of ... we all have our quirks.

- November 13th 2012, 05:06 PMDevenoRe: verifying trig identities
well, there is a reason for these things. for example, in modelling a physical situation, if one writes cos(t), the "t" is there presumably to remind you which UNITS "t" is in (often, in physics for example, one may have equations with respect to several variables at once, but one is considering some of the variables as "variable constants" or parameters chosen before-hand, whereas the independent variable might take on any value in the domain, so you can have cos(ωt), where ω is "fixed" but "t" is a "true variable", which might be important when differentiating).

of course, trigonometry is peculiar, too, it is one place where cos^{2}(x) means: (cos(x))(cos(x)), and not cos(cos(x)), like it would in other areas. - November 13th 2012, 06:19 PMWhatthePatelRe: verifying trig identities
I don't get why you multiplied it by secx+1/ secx+1?

- November 14th 2012, 04:20 AMskeeterRe: verifying trig identities