
Basic Trig problem
Simplify and write the trigonometric expression in terms of sine and cosine:
http://webwork.mathstat.concordia.ca...ac79325181.png
I put this as my answer
http://webwork.mathstat.concordia.ca...5d0e7888d1.png and I was told this Your answer isn't a number
(it looks like a formula that returns a number) I am figuring I have to reduce this?

Re: Basic Trig problem
The answer is actually 1. To show this, we have
$\displaystyle \tan^2 x  \sec^2 x = \frac{\sin^2 x}{\cos^2 x}  \frac{1}{\cos^2 x}$
$\displaystyle = \frac{\sin^2 x  1}{\cos^2 x}$
$\displaystyle = \frac{\cos^2 x}{\cos^2 x}$
$\displaystyle = 1$