Results 1 to 3 of 3
Like Tree1Thanks
  • 1 Post By skeeter

Math Help - Trig Identities Question

  1. #1
    Newbie
    Joined
    Nov 2012
    From
    Canada
    Posts
    9
    Thanks
    1

    Trig Identities Question

    sin2x-tan2x = -sin2xtan2x
    Thats my question. And also i really suck at identities so if you can
    maybe give me some tips on how to do better on them or how to make
    them easier, would be helpful. Cause i usually get scared as soon as i see them.
    Thank you.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    skeeter's Avatar
    Joined
    Jun 2008
    From
    North Texas
    Posts
    12,125
    Thanks
    1009

    Re: Trig Identities Question

    \sin^2{x} - \frac{\sin^2{x}}{\cos^2{x}} =

    \frac{\sin^2{x}\cos^2{x}}{\cos^2{x}} - \frac{\sin^2{x}}{\cos^2{x}} =

    \frac{\sin^2{x}\cos^2{x} - \sin^2{x}}{\cos^2{x}}

    \frac{\sin^2{x}(\cos^2{x} - 1)}{\cos^2{x}}

    \frac{\sin^2{x}(-\sin^2{x})}{\cos^2{x}}

    finish it ...
    Thanks from WhatthePatel
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Nov 2012
    From
    Canada
    Posts
    9
    Thanks
    1

    Re: Trig Identities Question

    Got it thanks
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. trig identities
    Posted in the Trigonometry Forum
    Replies: 4
    Last Post: August 10th 2010, 12:14 AM
  2. Trig identities help!
    Posted in the Trigonometry Forum
    Replies: 1
    Last Post: July 14th 2008, 02:33 PM
  3. Trig identities
    Posted in the Trigonometry Forum
    Replies: 5
    Last Post: March 7th 2008, 12:59 AM
  4. Quick and easy question trig identities
    Posted in the Pre-Calculus Forum
    Replies: 4
    Last Post: January 12th 2008, 04:37 PM
  5. Trig Identities
    Posted in the Trigonometry Forum
    Replies: 1
    Last Post: June 14th 2007, 12:51 PM

Search Tags


/mathhelpforum @mathhelpforum