# Math Help - Trig Identities Question

1. ## Trig Identities Question

sin2x-tan2x = -sin2xtan2x
Thats my question. And also i really suck at identities so if you can
maybe give me some tips on how to do better on them or how to make
them easier, would be helpful. Cause i usually get scared as soon as i see them.
Thank you.

2. ## Re: Trig Identities Question

$\sin^2{x} - \frac{\sin^2{x}}{\cos^2{x}} =$

$\frac{\sin^2{x}\cos^2{x}}{\cos^2{x}} - \frac{\sin^2{x}}{\cos^2{x}} =$

$\frac{\sin^2{x}\cos^2{x} - \sin^2{x}}{\cos^2{x}}$

$\frac{\sin^2{x}(\cos^2{x} - 1)}{\cos^2{x}}$

$\frac{\sin^2{x}(-\sin^2{x})}{\cos^2{x}}$

finish it ...

3. ## Re: Trig Identities Question

Got it thanks