x should be theta but I don't where the theta symbol is.

I need to find all the values of x, 0<=x<=2Pi for:

sin^{2}x=3/4

but the sin^{2}has thrown me out, can anyone please help?

Printable View

- November 7th 2012, 06:53 PMatpod1Help with finding values of sin^2x=3/4
x should be theta but I don't where the theta symbol is.

I need to find all the values of x, 0<=x<=2Pi for:

sin^{2}x=3/4

but the sin^{2}has thrown me out, can anyone please help? - November 7th 2012, 07:06 PMMarkFLRe: Help with finding values of sin^2x=3/4
Take the square root of both sides, what do you find?

- November 7th 2012, 07:23 PMatpod1Re: Help with finding values of sin^2x=3/4
sin x = square root of 3/4

- November 7th 2012, 07:32 PMMarkFLRe: Help with finding values of sin^2x=3/4
Don't forget the when you take the square root. So you have:

You will have 4 solutions on the given interval...can you find them? - November 7th 2012, 07:50 PMatpod1Re: Help with finding values of sin^2x=3/4
I see. The square root of 3/4 is, square root 3/2, which is Pi/3

Therefore as it is Positive in quadrants I and II the angle must be Pi - Pi/3 = 2Pi/3

so for + square root 3/2 the angles are Pi/3 and 2Pi/3

and for - square root 3/2 the angles are 4Pi/3 and 5Pi/3 - November 7th 2012, 07:54 PMMarkFLRe: Help with finding values of sin^2x=3/4
Yes, good work! :)

You found the quadrant I solution, then used the identity to get the quadrant II solution, then used the identity along with to get the quadrant III and IV solutions. - November 7th 2012, 08:03 PMatpod1Re: Help with finding values of sin^2x=3/4
You're a genius! Thank you for your help.

- November 8th 2012, 01:34 AMPetrusRe: Help with finding values of sin^2x=3/4
just think like normal equation when u solve sin,tan and cos :) the only diffrent is kinda you have to take away or add pi to get to your intervall :P. Took me so long time to understand this and its so simple (I feel stupid that i did not understand this alot early <.<) btw i recomend to always draw unit circle :)