Section B
Number 9) II
How do go about answering this?
Please see attached pdf
What i did
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cos2x=1-2sin275
cos 2x = cos (x+x)
cos (x+x) = cosA*CosB-SinA*SinB
cos( 60 + 90)= cos60*cos90 - sin60*cos90
answer i got was wrong
section B part III number 9
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cos 2x = cos2x - sin2x
cos( x + x) = cosA*CosB-SinA*SinB
cos(90 + 45)= cos90*cos45-sin90*sin45
I attempted this one similarly.. wrong answer... help!


1Thanks
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