in the problem in the above picture, how did they get from $\displaystyle 2cox+2sinxcox=0$ to $\displaystyle 2cosx(1+sinx)=0$?
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Hey kingsolomonsgrave. They are factoring out cos(x) of both sides. Remember that in distributive law if you have ab + ac, then you can factor this out to get a(b+c).
OH! of course, thanks!
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