Hey jessicahatesmath.

For 3) you will have three sets of inequalities and all you have to do is find the area that is common to all inequalities.

So in these examples, the easiest way to find the inequality is find the equality and then see which half is > and which half is <.

So in the equality we have 9x + 1y = 1700. To find this line we get two points on the line and the line is a straight line going through those two points.

So x = 0 means y = 1700 so one point is (0,1700). When y = 0 we get 9x = 1700 so x = 188.8889 (roughly) so another point is (1888.8889,0)

Now you can graph this line by joining a straight line between the two points using a ruler (if you don't have a computer program to do it).

Now you want 9x + y <= 1700 so we need to see whether above the line or below the line satisfies the inequality. Lets pick the origin (0,0). Then 9*0 + 1*0 = 0 <= 1700 so the region for this inequality is below the line formed by the two points (0,1700) and (188.8889).

Now do this for the other lines and see what region they all have in common.