We are given to solve:
where
Now, in turn equate both factors to zero, and solve for on the given interval:
The extra solutions you gave satisfy , which is not part of the original equation.
So this is the equation,
(sin x)^2 = sinx cosx for x lying between 0 and 360 degrees both inclusive.
Solving it, i got the following values for x
x = 0, 45 , 135 , 180 , 225 , 315 , 360
but the correct values for x are x = 0, 45 , 180 , 225 , 360
I dont understand why 135, 315 is not considered as correct .
Nid ur help guys. thnks in advance