Hello again,

The question I have been given is to find two positive angles for 1) arcsin(-.37) 2) arccos(-.37) and 3) arctan(-.37) in the range 0<θ<360.

Mainly the wording of the question is confusing me. I started with (sin^-1(−0.37)) and got -21.7 which I converted to 338° which was one correct answer. I then thought to take that angle and subtract 180° to get the 2nd angle in the II Quadrant, but 158 is not the correct answer. I don't understand what is meant by "2 positive angles between 0 and 360". Any suggestions?

Thanks