Hello. I am stuck at a point on this question.
Identify the maximum and minimum values of the function y = 10 cos x in the interval [-2π, 2π].
This is what I have so far (not much I know)
10 cos [-2π]=10
10 cos [2π]=10
f(x)=10 sin (x)
0=10 sin (x)
0=sin (x)
Nothing like the examples I was given in class so now I can't figure out what to do. Is anyone able to explain this to me please?
Thanks everybody.
So since -2pi would be the low end and 2pi would be the high end, and plugging those into the equation always equals 10, the minimum is -10 and maximum would be 10? Is that because cos 2pi and -2pi always equals 1?
I see.
The book wants me to explain my answer using transformations. So without using a calculator, could I say that since cos(2pi) is 1, any transformation of interval [-2π, 2π] would yield a stretch of or shrink of 10? Or am I going a little outbound on saying that?