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**Prove It** This is equivalent to $\displaystyle \displaystyle \begin{align*} \tan{\theta} = -\frac{1}{2} \end{align*}$. The tangent function has a period of $\displaystyle \displaystyle \begin{align*} \pi \end{align*}$, so to get the general solution, you need to write $\displaystyle \displaystyle \begin{align*} + \pi n \end{align*}$ where $\displaystyle \displaystyle \begin{align*} n \in \mathbf{Z} \end{align*}$ after $\displaystyle \displaystyle \begin{align*} -0.464 \end{align*}$.