1. Vector Projection Problem

Find another vector that has the same projection onto v=<1,1> as u=<1,2>.

2. Re: Vector Projection Problem

Find another vector that has the same projection onto v=<1,1> as u=<1,2>.
The vector projection of u onto v

$\frac{u \cdot v}{||v||^2}v=\frac{3}{2}<1,1>$

Now pick an arbitary vector $w=$

$\frac{w \cdot v}{||v||^2}v=\frac{a+b}{2}<1,1>$

If you compare these two vectors we see that

$a+b=3 \iff a=3-b$

So the vector is $<3-b,b>$

This will work for any choice of b

P.S go Beavs!!