1. ## HELP :::::: trigonometry PLEASE

Hello there, are you OK! I hope soooo

Brother and sisters, this is my last problem in my project and so would you please help me and I promise you that I’ll mention your names in my project I swear to GOD

So the problem is I want to know the lengths of the lines ( ae ), ( bf ) and ( cg )

Where AED=20.4, BFD= 13.52, CGD=10.8546 and PD= 10.2

Theta 1=30, Theta 2=50, Theta 3=70 and Theta 4= 90

sincerely

2. ## Re: HELP :::::: trigonometry PLEASE

Hello, hgphtgi!

I'll solve one part for you.

I want to know the lengths of $AE, BF, CG.$
where $AD=20.4,\:BD = 13.52,\:CD=10.8546,\:PD= 10.2$
. . $\theta_1=30^o,\;\theta_2=50^o,\:\theta_3=70^o,\: \theta_4= 90^o$

We will determine $AE.$
Code:
                      o D
* |
E  *   |
o     |
d  * |     | 10.2
*   |     |
*     |     |
* 30O - | - - |
A o - - - - + - - o P
: -  x  - Q 5.1 :
In right triangle $D\!P\!A$, we have:

. . $\tan30^o \:=\:\frac{10.2}{x+5.1} \quad\Rightarrow\quad x \;=\;\frac{10.2}{\tan30^o} - 5.1 \;=\;12.56691824$

Hence: . $x \:\approx\:12.57$

In right triangle $EQA$, we have:

. . $\cos30^o \:=\:\frac{x}{AE} \quad\Rightarrow\quad AE \:=\:\frac{12.57}{\cos30^o} \:=\:14.51458577$

Therefore: . $AE \;\approx\;14.5$