I'm doing a heat transfer lab report, and I need help solving this simplified equation for m.
.9761 = cosh(18.25m)/cosh(.25m)
This is going to be difficult, if not impossible, to solve by hand. Also according to my calculations the function
$\displaystyle f(m)=0.9761-\frac{\cosh(18.15m)}{\cosh(.25m)}$
has its absolute maximum at $\displaystyle x=0$
and it does not have any real solutions because
$\displaystyle f(0)=0.9761-1=-0.0239$