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Math Help - Help with hyperbolic cosine fraction

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    Help with hyperbolic cosine fraction

    I'm doing a heat transfer lab report, and I need help solving this simplified equation for m.

    .9761 = cosh(18.25m)/cosh(.25m)
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    Re: Help with hyperbolic cosine fraction

    Quote Originally Posted by Killswitch87 View Post
    I'm doing a heat transfer lab report, and I need help solving this simplified equation for m.

    .9761 = cosh(18.25m)/cosh(.25m)
    This is going to be difficult, if not impossible, to solve by hand. Also according to my calculations the function

    f(m)=0.9761-\frac{\cosh(18.15m)}{\cosh(.25m)}

    has its absolute maximum at x=0

    and it does not have any real solutions because

    f(0)=0.9761-1=-0.0239
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