# Thread: Help with hyperbolic cosine fraction

1. ## Help with hyperbolic cosine fraction

I'm doing a heat transfer lab report, and I need help solving this simplified equation for m.

.9761 = cosh(18.25m)/cosh(.25m)

2. ## Re: Help with hyperbolic cosine fraction

Originally Posted by Killswitch87
I'm doing a heat transfer lab report, and I need help solving this simplified equation for m.

.9761 = cosh(18.25m)/cosh(.25m)
This is going to be difficult, if not impossible, to solve by hand. Also according to my calculations the function

$f(m)=0.9761-\frac{\cosh(18.15m)}{\cosh(.25m)}$

has its absolute maximum at $x=0$

and it does not have any real solutions because

$f(0)=0.9761-1=-0.0239$