I'm doing a heat transfer lab report, and I need help solving this simplified equation for m.

.9761 = cosh(18.25m)/cosh(.25m)

Printable View

- September 28th 2012, 02:47 PMKillswitch87Help with hyperbolic cosine fraction
I'm doing a heat transfer lab report, and I need help solving this simplified equation for m.

.9761 = cosh(18.25m)/cosh(.25m) - September 28th 2012, 03:02 PMTheEmptySetRe: Help with hyperbolic cosine fraction