I'm doing a heat transfer lab report, and I need help solving this simplified equation for m.

.9761 = cosh(18.25m)/cosh(.25m)

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- Sep 28th 2012, 02:47 PMKillswitch87Help with hyperbolic cosine fraction
I'm doing a heat transfer lab report, and I need help solving this simplified equation for m.

.9761 = cosh(18.25m)/cosh(.25m) - Sep 28th 2012, 03:02 PMTheEmptySetRe: Help with hyperbolic cosine fraction
This is going to be difficult, if not impossible, to solve by hand. Also according to my calculations the function

$\displaystyle f(m)=0.9761-\frac{\cosh(18.15m)}{\cosh(.25m)}$

has its absolute maximum at $\displaystyle x=0$

and it does not have any real solutions because

$\displaystyle f(0)=0.9761-1=-0.0239$