# Help with hyperbolic cosine fraction

• Sep 28th 2012, 02:47 PM
Killswitch87
Help with hyperbolic cosine fraction
I'm doing a heat transfer lab report, and I need help solving this simplified equation for m.

.9761 = cosh(18.25m)/cosh(.25m)
• Sep 28th 2012, 03:02 PM
TheEmptySet
Re: Help with hyperbolic cosine fraction
Quote:

Originally Posted by Killswitch87
I'm doing a heat transfer lab report, and I need help solving this simplified equation for m.

.9761 = cosh(18.25m)/cosh(.25m)

This is going to be difficult, if not impossible, to solve by hand. Also according to my calculations the function

$f(m)=0.9761-\frac{\cosh(18.15m)}{\cosh(.25m)}$

has its absolute maximum at $x=0$

and it does not have any real solutions because

$f(0)=0.9761-1=-0.0239$