# Thread: pls help my problem

1. ## pls help my problem

give me the solution from the top of a building the angle of depression of a point on the same horizontal plane with the base of the building is observed to be 60 degree what will be the angle of depression of the same point when viewed from a position one third of the way up the building

2. ## Re: pls help my problem

If you draw a sketch, look at some ratios, you will find a nice relationship between the two angles of depression.

3. ## Re: pls help my problem

can u give a formula for my problem

4. ## Re: pls help my problem

Did you draw a sketch of the resulting triangles? Trigonometry frequently involves drawing diagrams and looking for similar triangles, etc.

5. ## Re: pls help my problem

can u give me the answer
for me

6. ## Re: pls help my problem

No, I'm not going to simply give you the answer. I will help you figure out how to do the problem...if you are willing to show some effort.

Put pen/pencil to paper, and draw a sketch. Tell us what you find, and we will be glad to help.

7. ## Re: pls help my problem

ok sir the triangle are two how can i find the formula can u help me pls

8. ## Re: pls help my problem

Okay, I assume you have labeled the distances and angles...

Using trigonometry, what is the ratio of the horizontal distance to the point to the height of the building?

Hint: use the tangent function. Do you see why?

edit: Or use the special angles within the larger triangle.

9. ## Re: pls help my problem

y can i use tangent funtion?

10. ## Re: pls help my problem

tan 60 degree is 10.23856

11. ## Re: pls help my problem

No, $\displaystyle \tan(60^{\circ})=\sqrt{3}$.

The reason the tangent function is useful here, is that it relates an angle in a right triangle to the ratio of the opposite to the adjacent side.

$\displaystyle \tan\theta=\frac{\text{opposite}}{\text{adjacent}}$

If $\displaystyle \theta=60^{\circ}$, what do the opposite and adjacent sides of the larger triangle represent?

0.57735

13. ## Re: pls help my problem

I have no idea where you got that number from, but there is no need for decimal equivalents.

In your diagram, what is the side that is opposite the 60° angle?