i was given this qn.... sin(A-B) = k sin(A+B)

sin(A-B) = sinAcosB + sinBcosA

= 1/2[sin(A+B)+sin(A-B)] - 1/2[sin(A+B)-sin(A-B)]

im not sure if im on the right track. cant seem to continue cos i will always return to sin(A-B)

PLEASE HELP!

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- Sep 23rd 2012, 05:42 AMZGOONTo solve K
i was given this qn.... sin(A-B) = k sin(A+B)

sin(A-B) = sinAcosB + sinBcosA

= 1/2[sin(A+B)+sin(A-B)] - 1/2[sin(A+B)-sin(A-B)]

im not sure if im on the right track. cant seem to continue cos i will always return to sin(A-B)

PLEASE HELP! - Sep 23rd 2012, 05:45 AMProve ItRe: To solve K
- Sep 23rd 2012, 11:00 PMZGOONRe: To solve K
cos i need to prove that sin(A-B) = k sin(A+B)

then from there i need to prove

tanA = [(1+k)/(1-k)] tanB