Find the remaining trigonometric ratios.

tan (a) = 4, 0<a<pi/2

sin( α)

=cos( α)

=cot( α)

=sec( α)

=csc( α)

=

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- September 19th 2012, 06:04 PMOldspice1212Trig Ratios
Find the remaining trigonometric ratios.

tan (a) = 4, 0<a<pi/2

sin( *α*)

=cos( *α*)

=cot( *α*)

=sec( *α*)

=csc( *α*)

= - September 19th 2012, 06:36 PMMarkFLRe: Trig Ratios
I would use the Pythagorean identities, keeping in mind all roots will be positive since the angle given is in the first quadrant. For example:

You can now easily find from . Now that you have the three primary functions, finding the rest is straightforward... - September 19th 2012, 06:43 PMOldspice1212Re: Trig Ratios
So would cos(a) be the same as sin (a), and the rest would be just reciprocals? Sorry I haven't done this in a long time :S

- September 19th 2012, 06:52 PMMarkFLRe: Trig Ratios
No, from the equation relating sin(a) and cos(a), we see that cos(a) is 1/4 the value of sin(a). Then yes, the secondary functions would be the reciprocals of the corresponding primary functions.

- September 19th 2012, 09:00 PMSorobanRe: Trig Ratios
Hello, Oldspice1212!

Quote:

Given: .

Find the remaining trigonometric ratios.

We are given: .

is in a right triangle with:

Pythagorus tells us that:

So we have: .

And we can write all six trig ratios:

. .