Parametric function involving trig

Hi all

I have this high school maths problem where i am given two equations which are parametric and am asked to find a cartesian equation from them. Normally i would be able to do this on my own, but i have never seen a question like this that involves two sin functions rather than a cos and sin

here are the equations

x=-4sin(Pi(t))/6) -(2pi)/3

and y=-3sin((Pi(t))/3) -pi

Any help would be greatly appreciated

Many thanks

Re: Parametric function involving trig

Quote:

=simoro1;735620Here are the equations

x=-4sin(Pi(t))/6) -(2pi)/3

and y=-3sin((Pi(t))/3) -pi

Hint: Use $\displaystyle \sin2\theta = 2\sin \theta \cos \theta$

Re: Parametric function involving trig

thanks man you've been a huge help