Find angle between 0 and pi that's coterminal with 17pi/6?

I know the answer is 5pi/6.

I just have no idea how to get that answer!

I understand coterminals when starting with a degree...add or subtract 360 to get between 0 and 360. That makes sense to me. But how do i find it when starting with a radian? Please Explain!!

Thank you! :)

Re: Find angle between 0 and pi that's coterminal with 17pi/6?

Quote:

Originally Posted by

**zoiberg137** I know the answer is 5pi/6.

I just have no idea how to get that answer!

I understand coterminals when starting with a degree...add or subtract 360 to get between 0 and 360. That makes sense to me. But how do i find it when starting with a radian? Please Explain!!

Thank you! :)

Well, $\displaystyle \displaystyle \begin{align*} 360^{\circ} = 2\pi^{C} \end{align*}$, so to find the coterminal angles are found by adding or subtracting multiples of $\displaystyle \displaystyle \begin{align*} 2\pi \end{align*}$.

Re: Find angle between 0 and pi that's coterminal with 17pi/6?

2pi to the square root of C???? What is C??? havent seen that yet...

Ok so I think I kind of understand how to subtract 2pi and come out with 5pi/6. But then how do I know thats between 0 and 2pi?? How do I know just from looking at it that the original problem, 17pi/6, isn't already between 0 and pi?

I feel like I have totally missed something here...I swear my book does not explain this lol.

Re: Find angle between 0 and pi that's coterminal with 17pi/6?

Quote:

Originally Posted by

**zoiberg137** 2pi to the square root of C???? What is C??? havent seen that yet...

Ok so I think I kind of understand how to subtract 2pi and come out with 5pi/6. But then how do I know thats between 0 and 2pi?? How do I know just from looking at it that the original problem, 17pi/6, isn't already between 0 and pi?

I feel like I have totally missed something here...I swear my book does not explain this lol.

C is the symbol for radians (literally means "number of lengths of the radius on the Circumference").

As for knowing if it's between 0 and $\displaystyle \displaystyle \begin{align*} 2\pi \end{align*}$, multiply $\displaystyle \displaystyle \begin{align*} 2\pi \end{align*}$ by the denominator (6) so that it looks like $\displaystyle \displaystyle \begin{align*} 2\pi = \frac{12\pi}{6} \end{align*}$. You can clearly see that $\displaystyle \displaystyle \begin{align*} \frac{17\pi}{6} > \frac{12\pi}{6} \end{align*}$.

Re: Find angle between 0 and pi that's coterminal with 17pi/6?

Quote:

Originally Posted by

**zoiberg137** I know the answer is 5pi/6.

I just have no idea how to get that answer!

I understand coterminals when starting with a degree...add or subtract 360 to get between 0 and 360. That makes sense to me. But how do i find it when starting with a radian? Please Explain!

Here is the way I think about.

If $\displaystyle 0\le\theta<2\pi$ then adding $\displaystyle 2k\pi,~k\in\mathbb{Z},$ gives an equivalent angle became each additional $\displaystyle 2\pi$ is a complete rotation.

Thus $\displaystyle \frac{17\pi}{6}=\frac{5\pi}{6}+2\pi.$

Re: Find angle between 0 and pi that's coterminal with 17pi/6?

how do we know which multiple of 2π to add/subtract?

we want:

0 ≤ 17π/6 + 2πk < 2π

multiply by 6:

0 ≤ 17π + 12πk < 12π

0 ≤ (17 + 12k)π < 12π

multiply by 1/π:

0 ≤ 12k + 17 < 12

subtract 17:

-17 ≤ 12k < -5

multiply by 1/12:

-17/12 ≤ k < -5/12

since k is an integer between -5/12 and -17/12, it must be that k = -1.

therefore the angle we want is:

17π/6 - 2π = 17π/6 - 12π/6 = 5π/6