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Math Help - Find angle between 0 and pi that's coterminal with 17pi/6?

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    Find angle between 0 and pi that's coterminal with 17pi/6?

    I know the answer is 5pi/6.

    I just have no idea how to get that answer!

    I understand coterminals when starting with a degree...add or subtract 360 to get between 0 and 360. That makes sense to me. But how do i find it when starting with a radian? Please Explain!!

    Thank you!
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    Re: Find angle between 0 and pi that's coterminal with 17pi/6?

    Quote Originally Posted by zoiberg137 View Post
    I know the answer is 5pi/6.

    I just have no idea how to get that answer!

    I understand coterminals when starting with a degree...add or subtract 360 to get between 0 and 360. That makes sense to me. But how do i find it when starting with a radian? Please Explain!!

    Thank you!
    Well, \displaystyle \begin{align*} 360^{\circ} = 2\pi^{C} \end{align*}, so to find the coterminal angles are found by adding or subtracting multiples of \displaystyle \begin{align*} 2\pi \end{align*}.
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    Re: Find angle between 0 and pi that's coterminal with 17pi/6?

    2pi to the square root of C???? What is C??? havent seen that yet...

    Ok so I think I kind of understand how to subtract 2pi and come out with 5pi/6. But then how do I know thats between 0 and 2pi?? How do I know just from looking at it that the original problem, 17pi/6, isn't already between 0 and pi?

    I feel like I have totally missed something here...I swear my book does not explain this lol.
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    Re: Find angle between 0 and pi that's coterminal with 17pi/6?

    Quote Originally Posted by zoiberg137 View Post
    2pi to the square root of C???? What is C??? havent seen that yet...

    Ok so I think I kind of understand how to subtract 2pi and come out with 5pi/6. But then how do I know thats between 0 and 2pi?? How do I know just from looking at it that the original problem, 17pi/6, isn't already between 0 and pi?

    I feel like I have totally missed something here...I swear my book does not explain this lol.
    C is the symbol for radians (literally means "number of lengths of the radius on the Circumference").

    As for knowing if it's between 0 and \displaystyle \begin{align*} 2\pi \end{align*}, multiply \displaystyle \begin{align*} 2\pi \end{align*} by the denominator (6) so that it looks like \displaystyle \begin{align*} 2\pi = \frac{12\pi}{6} \end{align*}. You can clearly see that \displaystyle \begin{align*} \frac{17\pi}{6} > \frac{12\pi}{6} \end{align*}.
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    Re: Find angle between 0 and pi that's coterminal with 17pi/6?

    Quote Originally Posted by zoiberg137 View Post
    I know the answer is 5pi/6.
    I just have no idea how to get that answer!
    I understand coterminals when starting with a degree...add or subtract 360 to get between 0 and 360. That makes sense to me. But how do i find it when starting with a radian? Please Explain!
    Here is the way I think about.
    If 0\le\theta<2\pi then adding 2k\pi,~k\in\mathbb{Z}, gives an equivalent angle became each additional 2\pi is a complete rotation.

    Thus \frac{17\pi}{6}=\frac{5\pi}{6}+2\pi.
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    Re: Find angle between 0 and pi that's coterminal with 17pi/6?

    how do we know which multiple of 2π to add/subtract?

    we want:

    0 ≤ 17π/6 + 2πk < 2π

    multiply by 6:

    0 ≤ 17π + 12πk < 12π

    0 ≤ (17 + 12k)π < 12π

    multiply by 1/π:

    0 ≤ 12k + 17 < 12

    subtract 17:

    -17 ≤ 12k < -5

    multiply by 1/12:

    -17/12 ≤ k < -5/12

    since k is an integer between -5/12 and -17/12, it must be that k = -1.

    therefore the angle we want is:

    17π/6 - 2π = 17π/6 - 12π/6 = 5π/6
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