4sinx-2cos(2x)=1
Please help, how to solve this equation
Thanks for answering
I solved quadratic equation 4u^2+4u-3=0 (sinx=u)
u1=1/2
u2=-1.5 (dont satisfy)
so sinx=1/2 but i need to write two separate answers, what x1 and x2 are, but i get this
x=(-1)^n * Pi/6 + 2Pin
how to write two answers from that one, which i learned? please help