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Math Help - Terminal Arm Location

  1. #1
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    Terminal Arm Location

    You are given

    Cos(theta) = -(5/13) .0<theta<2pi

    In which quadrant(s) can the terminal arm be,.

    I believe quadrants 2 and 4 but the back of the book is saying 2, and 3

    I think it is 2 and 4 because the points of its location could be (-5, 13) Q2 or (5, -13) Q4

    If i am wrong how do i solve it?

    THANKS ALOT,
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  2. #2
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    Re: Terminal Arm Location

    Quote Originally Posted by waleedrabbani View Post
    I think it is 2 and 4 because the points of its location could be (-5, 13) Q2 or (5, -13) Q4
    So, cosine is the x-coordinate. Do both of these points have negative x-coordinates?
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  3. #3
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    Re: Terminal Arm Location

    I still dont get it what points would i use?

    (-5, 13) and (-5, -13)

    13 is the hypotenouse it cant be negative can it?
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  4. #4
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    Re: Terminal Arm Location

    The two possible points are (-5, 12) and (-5, -12).
    Thanks from waleedrabbani
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  5. #5
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    Re: Terminal Arm Location

    Quote Originally Posted by emakarov View Post
    The two possible points are (-5, 12) and (-5, -12).
    Oh i see,

    Thanks
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  6. #6
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    Re: Terminal Arm Location

    Quote Originally Posted by waleedrabbani View Post
    You are given Cos(theta) = -(5/13) .0<theta<2pi
    In which quadrant(s) can the terminal arm be,.
    Well cos(\theta)=-\frac{5}{13} means that x=-5~\&~y=12\text{ or }x=5~\&~y=-12.
    That means \theta\in II\text{ or }III.
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