# Requiring help on graphing CSC

• Aug 25th 2012, 03:33 PM
waleedrabbani
Requiring help on graphing CSC
The function is Y= CSC(0.5x + 3.14)

Would the phase shift be pie units to the left? or pie/2 units to the left.?

would the asymptotes be affected by the phase shift?

if so, would i adjust the asymptotes to the new period first then adjust it to the phase shift or vice versa?

Thanks
sorry if its a stupid question
• Aug 25th 2012, 05:32 PM
Prove It
Re: Requiring help on graphing CSC
It's easiest to think of \displaystyle \displaystyle \begin{align*} \csc{X} = \frac{1}{\sin{X}} \end{align*}. The asymptotes are wherever \displaystyle \displaystyle \begin{align*} \sin{X} = 0 \end{align*} and the phase shift is surely the same as the phase shift for \displaystyle \displaystyle \begin{align*} \sin{X} \end{align*}...
• Aug 25th 2012, 05:41 PM
Plato
Re: Requiring help on graphing CSC
Quote:

Originally Posted by waleedrabbani
The function is Y= CSC(0.5x + 3.14)
Would the phase shift be pie units to the left? or pie/2 units to the left.?

This is what is stupid. Pie is an after-meal dish, as in apple pie.
$\displaystyle \pi$ (spelled pi) is a number. AND $\displaystyle \pi\neq 3.14$.
• Aug 25th 2012, 05:54 PM
waleedrabbani
Re: Requiring help on graphing CSC
Quote:

Originally Posted by Prove It
It's easiest to think of \displaystyle \displaystyle \begin{align*} \csc{X} = \frac{1}{\sin{X}} \end{align*}. The asymptotes are wherever \displaystyle \displaystyle \begin{align*} \sin{X} = 0 \end{align*} and the phase shift is surely the same as the phase shift for \displaystyle \displaystyle \begin{align*} \sin{X} \end{align*}...

Thanks that helps!

And plato im sorry if i offended you :P