God aften eller hej ,
the area A of a trapezium is calculated by $\displaystyle A_T = \frac{a+c}2 \cdot h$ where a and c denote the parallel sides and h the perpendicular distance of the parallels.
With your values the area is
$\displaystyle A_T = \frac{x+x+1.5}2 \cdot 3$
In fact the value of 63.43° is not necessary. Maybe there is an information missing where you need to know the value of this angle?
Hello, Enjubi!
I need to find the area of the trapezoid (from the slanted line and down).
How do I find $\displaystyle x$?Triangle $\displaystyle ABC$ can be placed higher or lower.Code:- *-----------------------* : | | : | | : | | : | *B : | * | 3 | * | 1.5 : | * | : A* - - - - - - - - - - - *C : | | : | |x : | | - *-----------------------* : - - - - - 3 - - - - - :
The distance $\displaystyle x$ can range from 0 to 1.5.