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Math Help - Trapez-Trouble

  1. #1
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    Trapez-Trouble

    Hello friend.
    I need to find the area of the trapez (from the leaning line and down).
    Obviously I need to find out how wide it is, but I'm not sure how since I can not come up with anything clever.
    Help me out here: How do I find X?

    Trapez-Trouble-trigo.png
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  2. #2
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    Re: Trapez-Trouble

    Quote Originally Posted by Enjubi View Post
    Hello friend.
    I need to find the area of the trapez (from the leaning line and down).
    Obviously I need to find out how wide it is, but I'm not sure how since I can not come up with anything clever.
    Help me out here: How do I find X?

    Click image for larger version. 

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    God aften eller hej ,

    the area A of a trapezium is calculated by A_T = \frac{a+c}2 \cdot h where a and c denote the parallel sides and h the perpendicular distance of the parallels.

    With your values the area is

    A_T = \frac{x+x+1.5}2 \cdot 3

    In fact the value of 63.43 is not necessary. Maybe there is an information missing where you need to know the value of this angle?
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  3. #3
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    Re: Trapez-Trouble

    Hello, Enjubi!

    I need to find the area of the trapezoid (from the slanted line and down).
    How do I find x?
    Code:
      -   *-----------------------*
      :   |                       |
      :   |                       |
      :   |                       |
      :   |                       *B
      :   |                 *     |
      3   |           *           | 1.5
      :   |     *                 |
      :  A* - - - - - - - - - - - *C
      :   |                       |
      :   |                       |x
      :   |                       |
      -   *-----------------------*
          : - - - - - 3 - - - - - :
    Triangle ABC can be placed higher or lower.

    The distance x can range from 0 to 1.5.
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