# Trapez-Trouble

• August 19th 2012, 06:15 AM
Enjubi
Trapez-Trouble
Hello friend.
I need to find the area of the trapez (from the leaning line and down).
Obviously I need to find out how wide it is, but I'm not sure how since I can not come up with anything clever.
Help me out here: How do I find X?

Attachment 24545
• August 19th 2012, 08:16 AM
earboth
Re: Trapez-Trouble
Quote:

Originally Posted by Enjubi
Hello friend.
I need to find the area of the trapez (from the leaning line and down).
Obviously I need to find out how wide it is, but I'm not sure how since I can not come up with anything clever.
Help me out here: How do I find X?

Attachment 24545

God aften eller hej (Smirk),

the area A of a trapezium is calculated by $A_T = \frac{a+c}2 \cdot h$ where a and c denote the parallel sides and h the perpendicular distance of the parallels.

With your values the area is

$A_T = \frac{x+x+1.5}2 \cdot 3$

In fact the value of 63.43° is not necessary. Maybe there is an information missing where you need to know the value of this angle?
• August 19th 2012, 01:54 PM
Soroban
Re: Trapez-Trouble
Hello, Enjubi!

Quote:

I need to find the area of the trapezoid (from the slanted line and down).
How do I find $x$?

Code:

  -  *-----------------------*   :  |                      |   :  |                      |   :  |                      |   :  |                      *B   :  |                *    |   3  |          *          | 1.5   :  |    *                |   :  A* - - - - - - - - - - - *C   :  |                      |   :  |                      |x   :  |                      |   -  *-----------------------*       : - - - - - 3 - - - - - :
Triangle $ABC$ can be placed higher or lower.

The distance $x$ can range from 0 to 1.5.