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Math Help - Trigonometric Ratio

  1. #1
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    Trigonometric Ratio

    Hi, I need help with this question I have. It's about basic trigonometric ratios, the question is in the attachment. I don't understand exactly what to do. Please help, thanks in advanced
    Attached Thumbnails Attached Thumbnails Trigonometric Ratio-capture.jpg  
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  2. #2
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    Re: Trigonometric Ratio

    The trig ratios can be remembered as SOH, CAH, TOA

     \sin{\theta} = \frac{\mbox{opposite}}{\mbox{hypoteneuse}}

     \cos{\theta} = \frac{\mbox{adjacent}}{\mbox{hypoteneuse}}

     \tan{\theta} = \frac{\mbox{opposite}}{\mbox{adjacent}}

    For the angle B, the adjacent arm of the triangle has a length 19 and the hypoteneuse has a length 27. These can be used directly to get the cosine ratio. To find the other two ratios you need the length of the arm opposite to B. Can you think of a formula that allows you to find this length?
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  3. #3
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    Re: Trigonometric Ratio

    Pythagorean theorem, thanks.
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