1/3x^2-5/6=1
3x√ x-1 +2√ (x-1)^3=0 ......... square root symbol is over the x-1 and x-1^3
x^3-26x^3/2=27
2x^2(2x-1)^1/3=4x(2x-1)^4/3
15/2^x-1=7
3^x-1 + 3^x+1 =30
Any help on any of thse problems would be appreciated!
Hello, etran3358!
I'll guess what the last one means . . .
3^x-1+3^x+1=30
3^x/3+3.3^x=30
10/3.3^x=30
3^x=9
3^x=3^2
x=2
If my solution is hard to read and understand,
it's because I typed it the way you did ...
no parentheses, no spaces.
This is what I meant . . .
We are given: .3^{x-1} + 3^{x+1} = 30
which equals: .(3^x)/3 + 3(3^x) = 30
add: .(10/3)(3^x) = 30
Multiply by 3/10: .3^x = 9
Hence: .3^x = 3^2
Therefore: .x = 2