1/3x^2-5/6=1

3x√ x-1 +2√ (x-1)^3=0 ......... square root symbol is over the x-1 and x-1^3

x^3-26x^3/2=27

2x^2(2x-1)^1/3=4x(2x-1)^4/3

15/2^x-1=7

3^x-1 + 3^x+1 =30

Any help on any of thse problems would be appreciated!

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- August 11th 2012, 10:19 PMetran3358solve each equation algebraically
1/3x^2-5/6=1

3x√ x-1 +2√ (x-1)^3=0 ......... square root symbol is over the x-1 and x-1^3

x^3-26x^3/2=27

2x^2(2x-1)^1/3=4x(2x-1)^4/3

15/2^x-1=7

3^x-1 + 3^x+1 =30

Any help on any of thse problems would be appreciated! - August 11th 2012, 10:25 PMProve ItRe: solve each equation algebraically
I can't read the first, third, fourth, fifth and sixth questions. Some brackets would be nice... LaTeX would be even nicer...

Go from here... - August 12th 2012, 07:00 AMSorobanRe: solve each equation algebraically
Hello, etran3358!

I'llwhat the last one means . . .*guess*

Quote:

3^x-1+3^x+1=30

3^x/3+3.3^x=30

10/3.3^x=30

3^x=9

3^x=3^2

x=2

If my solution is hard to read and understand,

it's because I typed it the waydid ...*you*

no parentheses, no spaces.

This is what I meant . . .

We are given: .3^{x-1} + 3^{x+1} = 30

which equals: .(3^x)/3 + 3(3^x) = 30

add: .(10/3)(3^x) = 30

Multiply by 3/10: .3^x = 9

Hence: .3^x = 3^2

Therefore: .x = 2

- August 12th 2012, 10:36 AMetran3358Re: solve each equation algebraically
is #1

- August 12th 2012, 10:39 AMetran3358Re: solve each equation algebraically
#3 is it's 26 x raished to the 3/2 power

- August 12th 2012, 10:44 AMetran3358Re: solve each equation algebraically
- August 12th 2012, 10:45 AMetran3358Re: solve each equation algebraically
- August 12th 2012, 10:46 AMetran3358Re: solve each equation algebraically
again i apologize if it's hard to read/understand ... i'm new to this site

also the last problem reads as 15 ALL OVER 2^x -1 which is equal to 7

any help would be well appreciated! - August 12th 2012, 12:18 PMetran3358Re: solve each equation algebraically
i wrote these questions clearer down below...please help!!

- August 12th 2012, 12:51 PMSorobanRe: solve each equation algebraically
Hello, etran3358!

You still need parentheses,

or learn to use LaTeX more accurately.

Quote:

is #1.

Can you see that this looks like: .

But it might be: .

- August 12th 2012, 01:06 PMSorobanRe: solve each equation algebraically
Hello, etran3358!

Quote:

We have: .

Factor: . .

. . . . . . . .

Therefore:

. .

. .

. .

- August 12th 2012, 04:20 PMskeeterRe: solve each equation algebraically
graded assignment ... thread closed