Here:

(1+cosx+isinx) divided by (sinx-i(1+cosx))

Write in trigonometry form.

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- July 27th 2012, 08:20 AMTiffanySimple trigonometry....But I cant solve it agian :(
Here:

(1+cosx+isinx) divided by (sinx-i(1+cosx))

Write in trigonometry form. - July 27th 2012, 08:42 AMProve ItRe: Simple trigonometry....But I cant solve it agian :(
- July 31st 2012, 03:27 AMTiffanyRe: Simple trigonometry....But I cant solve it agian :(
Thank you so much. that is exactly what I want. :))

- August 4th 2012, 10:19 PMreflection_009Re: Simple trigonometry....But I cant solve it agian :(
(1+cosx+isinx) /(sinx-i(1+cosx))=((2Cos^2(x/2)+i2sin(x/2)cos(x/2))/((2sin(x/2)cos(x/2))-i2Cos^2(x/2))

=(cos(x/2)+isin(x/2))/(sin(x/2)-icos(x/2))=(cos(x/2)+isin(x/2))/[(-i)((cos(x/2)+isin(x/2))]

=(-1)/i= i (proved in 3 steps)