Good Day,

I need help to prove the following

sin x + sin 2x + sin 3x + ... + sin nx = {sin (n/2)x sin [(n+1)/2]x}/ sin (x/2)

Can it be proved without using induction?

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- July 25th 2012, 12:04 AMdd86Proving of trigonometric summation
Good Day,

I need help to prove the following

**sin x + sin 2x + sin 3x + ... + sin nx = {sin (n/2)x sin [(n+1)/2]x}/ sin (x/2)**

Can it be proved without using induction? - July 25th 2012, 04:50 AMProve ItRe: Proving of trigonometric summation
- July 25th 2012, 04:52 AMdd86Re: Proving of trigonometric summation
I was just wondering if it could be done without using induction, that's why...

- July 26th 2012, 04:26 AMdd86Re: Proving of trigonometric summation
Good Day,

I've tried many things to help prove the above summation. However, I don't seem to be getting anywhere.

I've attached a copy of my most logical steps to prove the above summation. Whatever I've done from that point onwards i.e. applying addition and product to sum or sum to product formulas were not included as they were only rough workings.

Attachment 24353

I really hope some one can point me in the right direction to help me prove this.