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Math Help - I am stuck at a simple trigonometry problem again

  1. #1
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    I am stuck at a simple trigonometry problem again

    I have a simple question again:

    I have this problem:

    Given the points P(2,0,0). Q(4,3,-2) and R(-2,0,5) Find the coordinates for point S so that PQRS creates a parallelogram.

    What i have tried is this:

    Found the vector QP and the vector QR and then found S = WP + QR and that gave me [-9, -6, 5] and this does not conform with the answer in the textbook at all which is (-4,-3,7)
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  2. #2
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    Re: I am stuck at a simple trigonometry problem again

    Oops i found it, i offcourse have to add the vector to the point Q to find the point
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  3. #3
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    Re: I am stuck at a simple trigonometry problem again

    Quote Originally Posted by mariusg View Post
    Given the points P(2,0,0). Q(4,3,-2) and R(-2,0,5) Find the coordinates for point S so that PQRS creates a parallelogram.
    answer in the textbook at all which is (-4,-3,7)
    You could note that \[\overrightarrow {QP}  = \left\langle { - 2, - 3,2} \right\rangle
    So \overrightarrow {QP}+\left\langle { - 2, 0,5} \right\rangle=\left\langle { - 4,-3,7} \right\rangle
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