I am stuck at a simple trigonometry problem again

I have a simple question again:

I have this problem:

Given the points P(2,0,0). Q(4,3,-2) and R(-2,0,5) Find the coordinates for point S so that PQRS creates a parallelogram.

What i have tried is this:

Found the vector QP and the vector QR and then found S = WP + QR and that gave me [-9, -6, 5] and this does not conform with the answer in the textbook at all which is (-4,-3,7)

Re: I am stuck at a simple trigonometry problem again

Oops i found it, i offcourse have to add the vector to the point Q to find the point

Re: I am stuck at a simple trigonometry problem again

Quote:

Originally Posted by

**mariusg** Given the points P(2,0,0). Q(4,3,-2) and R(-2,0,5) Find the coordinates for point S so that PQRS creates a parallelogram.

answer in the textbook at all which is (-4,-3,7)

You could note that $\displaystyle \[\overrightarrow {QP} = \left\langle { - 2, - 3,2} \right\rangle $

So $\displaystyle \overrightarrow {QP}+\left\langle { - 2, 0,5} \right\rangle=\left\langle { - 4,-3,7} \right\rangle$