review your unit circle ...
at and
Hi, the problem is:
solve on the interval 0 ≤ x ≤ 2pi
2 sin^2 x - 3 sin x -2 = 0
I factored the equation to (2x + 1)(x - 2)
then separated to 2x + 1 = 0 and x - 2 = 0
finally sin x = -1/2 and sin x = 2
I figured out one of the x's equals 210 degrees or 7pi/6. Sin x = 2 does not seem like a solution. The given choices each have more than one possible solution, and I have only found one. How do I find the other ones?
A technical point- since x appears in the orginal equation, it is not a good idea to use "x" to represent "sin(x)". Use some other letter.
finally sin x = -1/2 and sin x = 2
I figured out one of the x's equals 210 degrees or 7pi/6. Sin x = 2 does not seem like a solution. The given choices each have more than one possible solution, and I have only found one. How do I find the other ones?