Hello,

The question is: Solve sin(x) = cos(2x) for all x.

My solution:

sin(x) = cos(2x)

sin(x) = sin(1/2 pi - 2x)

x = 1/2 pi - 2x

3x = 1/2 pi

x = 1/6 pi

However, the question says "solve for all x". I understand that fact that there are multiple x-es since both functions are periodic. But how do I find the other x-es? Please help!