Thread: Prove the triangle identity

Hi everybody, I need your help again. I have to prove the following identity:
(b-2*cos(c)*a)/(a*sin(c))+(c-2*cos(a)*b)/(b*sin(a))+(a-2*cos(b)*c)/(c*sin(b))=0
For every triangle (a,b,c represents length of sides and opposite angles)
I know I should use laws of sine and cosine but I couldn't complete it.
Also sorry for my post, I'm on my tablet so I didn't use equation editor.

Alpha - opposite of a
Beta - opposite of b
Gama - opposite of c

It would help if you would distinguish between "A", the measure of an angle, and "a", the length of the side opposite that angle.