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Math Help - Trig

  1. #1
    Member srirahulan's Avatar
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    Arrow Trig

    If tan A=\ sec2\alpha\  cot\pi prove that \frac{cos(A+\pi)}{cos(A-\pi)}=-tan^2 \alpha I tried this by simplifying the statement and finally i get \frac{cos(A - \pi)}{cosAcos\pi}=\frac{2cos^2\alpha}{2cos^2\alpha-1} then i can't simplify this prove.please help me!!!
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  2. #2
    MHF Contributor Amer's Avatar
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    Re: Trig

    do you mean by \pi the known pi or it is just another constant if it is the known pi then

     \cot \pi is undefind
    Last edited by Amer; June 9th 2012 at 08:14 PM.
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  3. #3
    Junior Member Tclack's Avatar
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    Re: Trig

    Quote Originally Posted by srirahulan View Post
    If tan A=\ sec2\alpha\  cot\pi
    is that secant supposed to be squared?
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  4. #4
    Member srirahulan's Avatar
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    Re: Trig

    pi is a constant.i am really sorry to undefind it.
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  5. #5
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    Re: Trig

    The question doesn't seem to make much sense anyway, doesn't \frac{\cos(A+\pi)}{\cos(A-\pi)}=1 ?
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  6. #6
    Junior Member Tclack's Avatar
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    Re: Trig

    Well, IF you meant sec squared(you didn't get back to me, so idk), then maybe This looks like it's getting somewhere

    Trig-trigprob.jpg
    it looks like the right side will reduce to -1, so you can substitute in that cos(A+pi)/cos(A-pi) = 1 from above
    Last edited by Tclack; June 10th 2012 at 07:04 AM. Reason: math error in image
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