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- May 29th 2012, 08:52 AMsrirahulanTrig Prove
- May 29th 2012, 09:13 AMabhayrickuRe: Trig Prove
sinn2a + sin2b = 2sin(a+b)cos(a-b)

=2sinc{cos(a-b)}

lhs becomes

=2sinc{cos(a-b)} + sin2c

=2sinc{cos(a-b) + cosc}

=2sinc{cos(a-b) - cos(a+b)}

=4sina.sinb.sinc=rhs