Thread: Logarithmic Relationships

How would i solve this?

Log3^9-log3^27+log3^243

Originally Posted by strdatmage

How would i solve this?
Log3^9-log3^27+log3^243

There is nothing there to solve.
If you want to add those up then:
where

Originally Posted by Plato

There is nothing there to solve.
If you want to add those up then:
where

It says : Write each expression as a single logarithm. B. Find the value of each expression

Originally Posted by strdatmage

It says : Write each expression as a single logarithm. B. Find the value of each expression

That is exactly what I posted.
Now you do some work for yourself.

Okay, so just Do that and replace L With 3?

Originally Posted by strdatmage

It says : Write each expression as a single logarithm. B. Find the value of each expression

As Plato demonstrated, you can use this property of logarithms:

.

Then combine like terms. You should familiarize yourself with basic logarithmic identities. Consult your textbook for information.

Originally Posted by strdatmage

How would i solve this?

Log3^9-log3^27+log3^243

I'm a little bit confused about the writing of this sum ...

Could it be that the original term was:



If so the final result is 4.

Originally Posted by strdatmage

It says : Write each expression as a single logarithm. B. Find the value of each expression

9L + 27L + 243L = 279L; where L = log(3)

279log(3) is the single logarithm
Use your calculator to find the value the appropriate base as it wasn't detailed here (assuming base e or base 10)