How would i solve this?
Log3^9-log3^27+log3^243
Printable View
How would i solve this?
Log3^9-log3^27+log3^243
There is nothing there to solve.Quote:
Originally Posted by strdatmage
If you want to add those up then:
where
It says : Write each expression as a single logarithm. B. Find the value of each expressionQuote:
Originally Posted by PlatoThere is nothing there to solve.
If you want to add those up then:
That is exactly what I posted.Quote:
Originally Posted by strdatmage
Now you do some work for yourself.
Okay, so just Do that and replace L With 3?
As Plato demonstrated, you can use this property of logarithms:Quote:
Originally Posted by strdatmage
.
Then combine like terms. You should familiarize yourself with basic logarithmic identities. Consult your textbook for information.
I'm a little bit confused about the writing of this sum ...Quote:
Originally Posted by strdatmage
Could it be that the original term was:
If so the final result is 4.
9L + 27L + 243L = 279L; where L = log(3)Quote:
Originally Posted by strdatmage
279log(3) is the single logarithm
Use your calculator to find the value the appropriate base as it wasn't detailed here (assuming base e or base 10)