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Math Help - Sine Rule

  1. #1
    Junior Member
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    Exclamation Sine Rule

    Hi!

    I'm not sure why I cannot get the answer. Could you please offer some assistance? Thank you very much.

    A and B are 2 balloons at the same height and 1000 metres apart. O is a ground observation position, angle AOX = 14 degrees, 15 minutes and angle BOX = 10 degrees, 30 minutes. Find the height of the balloons.

    So ... In triangle AOB, 1000 / sin 3' 45" = AO / sin 10'30" (where ' = degrees, " = minutes)
    AO = 1539.11 ...
    In triangle AOH (where H is the pt joining A to OX perpendicularly), Height / AO = sin 14'15"
    Height = 1529.32 ... m (but the answer is 686!)
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  2. #2
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    Re: Sine Rule

    Check your calculation.

    Another method.

    Use tan(14^o 15') = h/x
    and tan(10^o 30') = h/(1000 + x)
    Solve for x and then find h.
    Last edited by sa-ri-ga-ma; May 19th 2012 at 03:00 AM.
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  3. #3
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    Re: Sine Rule

    Thanks!
    Last edited by Sunyata; May 25th 2012 at 04:22 AM.
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