Check your calculation.
Use tan(14^o 15') = h/x
and tan(10^o 30') = h/(1000 + x)
Solve for x and then find h.
I'm not sure why I cannot get the answer. Could you please offer some assistance? Thank you very much.
A and B are 2 balloons at the same height and 1000 metres apart. O is a ground observation position, angle AOX = 14 degrees, 15 minutes and angle BOX = 10 degrees, 30 minutes. Find the height of the balloons.
So ... In triangle AOB, 1000 / sin 3' 45" = AO / sin 10'30" (where ' = degrees, " = minutes)
AO = 1539.11 ...
In triangle AOH (where H is the pt joining A to OX perpendicularly), Height / AO = sin 14'15"
Height = 1529.32 ... m (but the answer is 686!)