How do i figure out which period the function is in?
Im doing the problem 3 tan^{2 }x-1=0
i got tan x= 1sqrt 3 i have to find a solution to x. How do i know tan is on the interval 0, pi and not 0, 2pi?
The period of a periodic function is the smallest positive real number such that for all in the domain of the function. In case of for all real and no positive real number smaller than satisfies for all (It's true that for all but is not the smallest such positive real number.)