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Thread: trig and solve

  1. May 16th 2012, 08:22 PM #1
    srirahulan
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    Lightbulb trig and solve

    \cot \frac{\pi}{24} = \frac {2-\sqrt3}{\sqrt6 - \sqrt2 - 1}Simplify and find out value of the \cot\frac{\pi}{24}
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  2. May 17th 2012, 06:38 AM #2
    skeeter
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    Re: trig and solve

    \frac{2-\sqrt{3}}{\sqrt{6} - (\sqrt{2}+1)} \cdot \frac{\sqrt{6} + (\sqrt{2}+1)}{\sqrt{6} + (\sqrt{2}+1)}

    \frac{2\sqrt{6} + 2\sqrt{2} + 2 - 3\sqrt{2} - \sqrt{6} - \sqrt{3}}{6 - (2 + 2\sqrt{2} + 1)}

    \frac{\sqrt{6} - \sqrt{2} - \sqrt{3} + 2}{3 - 2\sqrt{2}} \cdot \frac{3 + 2\sqrt{2}}{3 + 2\sqrt{2}}

    \frac{3\sqrt{6} - 3\sqrt{2} - 3\sqrt{3} + 6 + 4\sqrt{3} - 4 - 2\sqrt{6} + 4\sqrt{2}}{9-8}

    \sqrt{6} + \sqrt{2} + \sqrt{3} + 2
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