hi guys i know very well on how to solve equtions like this but im a little confused with this one, im thinking the answear is just 1? (In(x))^2=In(x)^2
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Originally Posted by iFuuZe hi guys i know very well on how to solve equtions like this but im a little confused with this one, im thinking the answear is just 1? (In(x))^2=In(x)^2 Is this the equation? $\displaystyle (\ln x)^2=\ln(x^2)$ Using our properties of logarithms, we have $\displaystyle (\ln x)^2=2\ln x$ $\displaystyle (\ln x)^2-2\ln x=0$ $\displaystyle (\ln x)(\ln x - 2) = 0$
is this helpful..? $\displaystyle (\ln x)^2 = \ln (x^2) \rightarrow (\ln x)(\ln x) = \ln (x \cdot x)$
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