Results 1 to 3 of 3

Math Help - trig identities help needed solving????

  1. #1
    Newbie
    Joined
    May 2012
    From
    kanaida
    Posts
    17

    trig identities help needed solving????

    1/sec + tan = sec - tan
    prove one side equals to another BY SOLVING ONE SIDE ONLY
    Last edited by koolaid123; May 9th 2012 at 11:46 PM.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Senior Member
    Joined
    Nov 2011
    From
    Crna Gora
    Posts
    420
    Thanks
    64

    Re: trig identities help needed solving????

    \frac{1}{\sec \alpha+\tan \alpha}=\frac{1}{\frac{1}{\cos \alpha}+\frac{\sin \alpha}{\cos \alpha}}=\frac{\cos \alpha}{1+\sin \alpha} \cdot \frac{1-\sin \alpha}{1-\sin \alpha}=\frac{\cos \alpha \cdot(1-\sin \alpha)}{\cos^2 \alpha}=\frac{1-\sin \alpha}{\cos \alpha}=\frac{1}{\cos \alpha}-\tan \alpha=\sec \alpha-\tan \alpha
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Super Member
    Joined
    Jun 2009
    Posts
    663
    Thanks
    133

    Re: trig identities help needed solving????

    The LHS should be 1/(\sec\theta+\tan\theta). Multiply top and bottom by (\sec\theta-\tan\theta) .
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. trig identities help needed
    Posted in the Trigonometry Forum
    Replies: 2
    Last Post: September 4th 2010, 07:42 PM
  2. Solving with Trig Identities..
    Posted in the Trigonometry Forum
    Replies: 2
    Last Post: December 3rd 2009, 11:14 AM
  3. Solving Trig Identities! HELP!
    Posted in the Trigonometry Forum
    Replies: 4
    Last Post: February 5th 2009, 04:24 PM
  4. Solving Trig Identities??
    Posted in the Trigonometry Forum
    Replies: 5
    Last Post: January 13th 2009, 04:36 PM
  5. Solving Trig Identities
    Posted in the Trigonometry Forum
    Replies: 10
    Last Post: May 24th 2008, 06:13 PM

Search Tags


/mathhelpforum @mathhelpforum